# Step increment and replace

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created January 25, 2006 · complexity intermediate · author Gerald Lai · version 6.0

This allows a search, and step-by-step confirm & replace, while having the replace string incremented each time if it contains a number at the end of the string. To search for occurrences of "abc", to replace with "xyz0" for the first "abc", "xyz1" for the second "abc", etc, simply do:

```:SReplace abc xyz0 1
```

At any step, you can change from "xyzN" to "defN", and pick up where you left off with the same increment.

```Usage: SReplace <search> <substitute> <increment>
```
```command -nargs=+ SReplace call StepReplace(<f-args>)
"makes use of register y
function StepReplace(...)
if a:0 == 1
let @y = input("Replace with: ", @y)
let y = @y
if @y =~ "\\d\\+\$"
let n = substitute(@y, ".\\{-}\\(\\d\\+\\)\$", "\\1", "") + a:1
let @y = substitute(@y, "\\(.\\{-}\\)\\d\\+\$", "\\1".n, "")
endif
return y
elseif a:0 == 3
let @y = a:2
execute "%s/".a:1."/\\=StepReplace(".a:3.")/".(&gdefault ? "" : "g")."c"
else
echo "Usage: SReplace <search> <substitute> <increment>"
endif
endfunction
```